Namespace ManagedCuda.VectorTypes

Structs

CUDA dim3. In difference to the CUDA dim3 type, this dim3 initializes to 0 for each element. dim3 should be value-types so that we can pack it in an array. But C# value types (structs) do not garantee to execute an default constructor, why it doesn't exist.

double1

double2

double3

double4

float1

float2

float3

float4

int1

int2

int3

int4

long1

long1. long stands here for the long .NET type, i.e. long long or a 64bit long in C++/CUDA

long2

long2. long stands here for the long .NET type, i.e. long long or a 64bit long in C++/CUDA

long3

long3. long stands here for the long .NET type, i.e. long long or a 64bit long in C++/CUDA

long4

long4. long stands here for the long .NET type, i.e. long long or a 64bit long in C++/CUDA

short1

short2

short3

short4

uchar1

uchar2

uchar3

uchar4

uint1

uint2

uint3

uint4

ulong1

ulong1. ulong stands here for the ulong .NET type, i.e. unsigned long long or a 64bit unsigned long in C++/CUDA

ulong2

ulong2. ulong stands here for the ulong .NET type, i.e. unsigned long long or a 64bit unsigned long in C++/CUDA

ulong3

ulong3. ulong stands here for the ulong .NET type, i.e. unsigned long long or a 64bit unsigned long in C++/CUDA

ulong4

ulong4. ulong stands here for the ulong .NET type, i.e. unsigned long long or a 64bit unsigned long in C++/CUDA

ushort1

ushort2

ushort3

ushort4

Interfaces

ICudaVectorType

Define a common interface for all CUDA vector types See http://blogs.msdn.com/b/ricom/archive/2006/09/07/745085.aspx why these vector types look like they are.

ICudaVectorTypeForArray

Define a common interface for all CUDA vector types supported by CudaArrays